scrapy的post登录:renren[通俗易懂]

(29) 2023-03-27 15:08

Hi,大家好,我是编程小6,很荣幸遇见你,我把这些年在开发过程中遇到的问题或想法写出来,今天说一说scrapy的post登录:renren[通俗易懂],希望能够帮助你!!!。
scrapy的post登录:renren[通俗易懂]_https://bianchenghao6.com/blog__第1张

# -*- coding: utf-8 -*-
import scrapy


class RenrenSpider(scrapy.Spider):
    name = 'renren'
    allowed_domains = ['renren.com']
    # 修改起始的请求
    start_urls = ['http://www.renren.com/PLogin.do']

    def start_requests(self):
        # 构建url
        url = self.start_urls[0]
        # 构建请求数据
        post_data = {
            'email': '17173805860',
            'password': '1qaz@WSX3edc'
        }

        # 发送请求
        yield scrapy.FormRequest(url,formdata=post_data)


    def parse(self, response):
        with open('renren.html','wb')as f:
            f.write(response.body)

scrapy  如何发送post请求。代码如上。

 

方法二:针对从首页重定向到登录页面的post登录

# -*- coding: utf-8 -*-
import scrapy


class RenrenFormSpider(scrapy.Spider):
    name = 'renren_form'
    allowed_domains = ['renren.com']
    start_urls = ['http://renren.com/']

    def parse(self, response):
        # 构建post数据
        post_data = {
            'email': '17173805860',
            'password': '1qaz@WSX3edc'
        }
        yield scrapy.FormRequest.from_response(response,formdata=post_data,callback=self.after_login)


    def after_login(self, response):
        with open('renrne2.html','w')as f:
            f.write(response.text)

  

转载于:https://www.cnblogs.com/andy9468/p/8299636.html

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